DC Wire Size Calculator
Pick a copper wire size for a DC run from current, one-way length, and a voltage-drop budget — checked against NEC ampacity, not drop alone.
Results
Recommended copper wire: 6 AWG
Voltage drop is what sizes this cable.
Circular mils the drop formula asks for: 21,500
Circular mils of the recommended gauge: 26,240
Voltage drop on the recommended gauge: 0.29 V (2.46%)
Voltage at the load: 11.71 V
Heat lost in the cable: 5.89 W
Ampacity the cable must cover: 20 A
Effective ampacity of the recommended gauge: 65 A
How it works
A DC cable has to clear two independent checks: voltage drop on the round-trip run, and the current the copper (and its breaker) can carry. The circular-mil formula finds the drop-limited size; the pick is the smallest AWG that also passes the NEC ampacity table.
required_cm = 2 × K × I × L / VD
VD = system_voltage × (voltage_drop_pct / 100)
actual_drop_v = 2 × L × (R / 1000) × I
ampacity_need = I, or I × 1.25 if continuous
recommended = smallest AWG with cmil ≥ required_cm
AND actual_drop_v ≤ VD
AND effective_ampacity ≥ ampacity_need
K- 12.9 — IAEI copper k-factor at 75 °C, derived from NEC Chapter 9 Table 8 (ohm/kFT × circular mils).
I- DC current on the run, in amperes. DC-side watts divide by voltage; inverter AC watts divide by battery voltage × 0.90 (same as the inverter-size tool). Voltage drop uses this number even when the load is continuous.
L- One-way length in feet. Both formulas multiply by 2 for the return conductor.
VD- Allowed drop in volts: system voltage × (budget percent ÷ 100). At 12 V and 3% that is 0.36 V.
required_cm- Minimum circular mils from the k-factor formula. A gauge still has to beat this number.
actual_drop_v- Round-trip drop using that gauge's Table 8 stranded resistance at 75 °C, not the rounded k-factor.
ampacity_need- Current the conductor must be rated for. Continuous loads (3+ hours at a stretch) are multiplied by 1.25. 14/12/10 AWG then take the 240.4(D) cap of 15/20/30 A.
Assumptions
- Copper stranded cable only. Aluminum needs a different k-factor (about 21.2) and is not in v1.
- Length is one way. Entering a round-trip distance would double the drop a second time.
- Resistance is NEC Chapter 9 Table 8 at 75 °C, which matches 75 °C terminations (110.14(C)). Charts published at 20–30 °C (some marine tables) read about one size smaller.
- 14/12/10 AWG copper are capped at 15/20/30 A by NEC 240.4(D), even though Table 310.16 lists 20/25/35 A at 75 °C.
- 3% is the NEC 210.19 informational-note convention for a branch, not a mandatory Code rule. Feeder-plus-branch totaling 5% is the matching note.
- The 125% factor applies only to ampacity, and only when you mark the run continuous. Voltage drop stays on the amps you entered.
- A = W ÷ V is only correct for DC-side watts. Inverter AC output still has to cover inverter loss: A = W ÷ (V × 0.90), the same 90% default as the inverter-size tool. A 1,200 W inverter on 12 V is about 111 A on the DC cable, not 100 A.
- This tool sizes the conductor. It does not pick a fuse or breaker, place the OCPD, or apply ambient / bundling derates from 310.15.
- Boat and RV cable charts (ABYC E-11, some chassis-harness tables) are not the NEC table. They can recommend a different gauge for the same amps and feet.
FAQ
What size wire for 30 amps at 12 volts?
It depends on length. At the default 15 ft one-way and a 3% budget, 30 A on 12 V needs 4 AWG copper (6 AWG drops 3.7%). A 5 ft run of the same current is mostly an ampacity problem: 10 AWG would nearly hold 3%, but NEC 240.4(D) caps it at 30 A, so a continuous 30 A load still steps up.
Is 3% voltage drop a code requirement?
No. NEC 210.19's 3% / 5% figures sit in an informational note — they describe reasonable efficiency, they do not require a size. A 12 V inverter input is unforgiving of sag, so 3% is still the sensible default. Tighten it to 2% for electronics; loosen it only when you accept the extra heat.
Is wire length one-way or round trip?
One way — battery to the load. Both the circular-mil formula and the Table 8 resistance check multiply by 2 for the return conductor. If you type a round-trip tape measure, the drop is counted twice and the wire comes out a size (or two) heavy.
Sources
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